Solveeit Logo

Question

Physics Question on Refraction of Light

Suppose refractive index μ\mu is given as μ=A+Bλ2\mu=A+\frac{B}{\lambda^{2}}, where AA and BB are constants and λ\lambda is wavelength then the dimensions of BB are same as that of

A

wavelength

B

pressure

C

area

D

volume

Answer

area

Explanation

Solution

We know that energy equation relating physical quantity should be in dimensional balance.
Hence, dimensions of terms on both sides of given equation must be same.
Given, μ=A+Bλ2 \mu=A+\frac{B}{\lambda^{2}}
where refractive index is a dimensionless quantity,
hence Bλ2\frac{B}{\lambda^{2}} is also dimensionless
\therefore Dimension of B=B= dimension of λ2\lambda^{2}
=cm2= cm ^{2}
== dimensions of area