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Question

Physics Question on laws in physics

Suppose refractive index μ\mu is given as μ=A+Bλ2 \mu = A + \frac{B}{\lambda^2} where A and B are constants and λ\lambda is wavelength, then dimensions of B are same as that of

A

wavelength

B

volume

C

pressure

D

area

Answer

area

Explanation

Solution

μ=velocityoflightinvacuumvelocityoflightinmedium\mu = \frac { velocity \, of \, light \, in \, vacuum }{ velocity \, of \, light \, in \, medium }
The refractive index μ \mu is dimensionless, so each term on right hand side is dimensionless. Hence, Bλ2 \frac{ B }{ \lambda^2 } is dimensionless.
This implies that dimensions of B will have the dimensions of
λ2\lambda^2 ie, of area. ie, of cm2cm^2 or area.