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Question

Question: Suppose refractive index μ is given as, μ = A + \(\frac{B}{\lambda^{2}}\) where A and B are constan...

Suppose refractive index μ is given as, μ = A + Bλ2\frac{B}{\lambda^{2}}

where A and B are constants and λ is wavelength, then dimensions of B are same as that of –

A

Wavelength

B

Volume

C

Pressure

D

Area

Answer

Area

Explanation

Solution

μ = A + Bλ2\frac{B}{\lambda^{2}} ⇒ B = [L2] = Area