Question
Mathematics Question on Combinations
Suppose r=0∑2023r22023Cr=2023×α×22022 Then the value of α is
Answer
The correct answer is 1012.
using result
r=0∑nr2nCr=n(n+1)⋅2n−2
Then r=0∑2023r22023Cr=2023×2024×22021
=2023×α×22022 So,
⇒α=1012