Question
Question: Suppose a truck starts rest with an acceleration of \[1.5m{s^{ - 2}}\] while a car \[150m\]behind st...
Suppose a truck starts rest with an acceleration of 1.5ms−2 while a car 150mbehind starts from rest with an acceleration of2ms−2.
Then find how long will it take before both the truck and car are side by side,
And also find the distance travelled by each.
Solution
In order to answer this question at first we must find time taken by the object during displacement and also the initial , final velocity and acceleration . Here we use the equation of motion to finding displacement i.e. ⇒S=ut+21at2
Complete step by step solution:
From this question we get –
Velocity of car=2s2m,
Velocity of truck=1.5s2m,
Therefore the relative velocity between the car and the truck will be
Now let the Initial velocity u=0
Now by applying the distance formula of motion –
⇒S=ut+21at2
⇒150=0+21×105t2
⇒150=21×105t2
⇒53000=t2
Therefore, time take before both the truck and the car are side by side is 24.5s
Again, given Uniform acceleration of truck utruck=0
And uniform acceleration of car ucar=0
(Acceleration) atruck=1.5s2m and acar=2s2m
So, Distance travelled by the truck Struck=ut+21at2
Struck=21×1.5(24.5)2
Struck=450.19
So, distance travelled by car Scar=ut+21at2
Scar=21×2×(24.5)2
Scar=(24.5)2
Scar=600.25
Note:
If there are no external forces applied on the object then its keep remains in the same state. This is defined by scientist Newton as “Law of Inertia”. If an object starts late after a vehicle then it will cross the vehicle which started first only if the velocity of the second vehicle is more that the initial vehicle.