Question

Suppose $a, b$ and $c$ are real numbers such that $\frac{a}{b}>1$ and $\frac{a}{c}<0$ . Which one of the following is true?

• A. $a+b-c>0$
• B. $a>b$
• C. $(a-c)(b-c)>0$
• D. $a+b+c>0$

Answer 1

Answer: (C)

$(a-c)(b-c)>0$

Answer 2

Given conditions are
$\frac{a}{b}>1$ and $\frac{a}{c}<0$ 1. $a>0$ iff $c<0$ and also $b>0$ 2. $a<0$ iff $c>0$ and also $b<0$
Hence, option satisfy the inequality.