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Question

Question: \(\sum_{k = 0}^{10}{20C_{k}}\) =...

k=01020Ck\sum_{k = 0}^{10}{20C_{k}} =

A

219 + 12\frac{1}{2}20 C10

B

219

C

20C10

D

None of these

Answer

219 + 12\frac{1}{2}20 C10

Explanation

Solution

S = 20C0 + 20C1 + 20C2 + ……… 20C10

2S = (20C0 + 20C1 + … 20C10) + 20C10

2S = 220 + 20C10

S = 219 + 12\frac{1}{2} 20C10