Question
Question: Sum of the series S = 1 +\(\frac{1}{2}\) (1 + 2) +\(\frac{1}{3}\) (1 + 2 + 3) + \(\frac{1}{4}\) (1 +...
Sum of the series S = 1 +21 (1 + 2) +31 (1 + 2 + 3) + 41 (1 + 2 + 3 + 4) …….. up to 20 terms is
A
110
B
111
C
115
D
116
Answer
115
Explanation
Solution
tr = r1 (1 + 2 + 3 ….. + r) = r1.21r (r + 1)
S = åtr = 21∑r=1n(r+1) = 115