Sulphuryl chloride ((SO\_2Cl\_2)) reacts with white phosphor... | Chemistry | SolveeIt

Question

Sulphuryl chloride $(SO_2Cl_2)$ reacts with white phosphorus $(P_4)$ to give

$PCl_5, \, SO_2$

$OPCl_3,\, SOCl_2$

$PCl_5,\, SO_2,\, S_2Cl_2$

$OPCl_3,\, SO_2,\, S_2Cl_2$

Answer

$PCl_5, \, SO_2$

Explanation

Solution

The correct answer is A: $PCl_5, \, SO_2$
When sulphuryl chloride $\left( SO _{2} Cl _{2}\right)$ reacts with white phosphorus $\left( P _{4}\right)$ , it give phosphorus pentachloride $\left( PCl _{5}\right)$ and' sulphur dioxide $\left( SO _{2}\right)$ . The reaction is as follows:
$P _{4}+10\, SO _{2} Cl _{2} \longrightarrow 4 PCl _{5}+10 SO _{2}$

Chemistry Question on p -Block Elements

Solution