Question

Sulphuryl chloride, $SO_2Cl_2$, reacts with $H_2O$ to give mixture of $H_2SO_4$ and HCl. Aqueous solution of 1 mol $SO_2Cl_2$ will be neutralised by

• A. 3 moles of NaOH
• B. 2 moles of $Ca(OH_2)$
• C. Both (A) and (B)
• D. None of these

Answer 1

Answer: (B)

2 moles of $Ca(OH_2)$

Answer 2

$\underset{\text{1 mol}}{ {SO_{2}Cl_{2}}}+ \underset{\text{2 mol}}{ {2H_{2}O}}\to \underset{\text{1 mol}}{ {H_{2}SO_{4}}}+\underset{\text{2 mol}}{ {2 HCl}}$ $\underset{\text{1 mol}}{ {H_{2}SO_{4}}}+ \underset{\text{2 mol}}{ {2NaOH}}\to Na_{2}SO_{4}+H_{2}O$ $\underset{\text{1 mol}}{ {HCl}}+\underset{\text{1 mol}}{ {NaOH}}\to NaCl+H_{2}]\times2$ $\therefore$ $1$ mol of $SO_{2}Cl_{2}$ in a solution requires $4$ mol of $NaOH$ or $2$ mol of $Ca(OH)_{2}$