Question

Sulphuric acid is a dibasic acid. Hence, it forms
(A)- Acidic salts
(B)- Basic salts
(C)- Acidic and normal salts
(D)- Double salts

Answer 1

Sulphuric acid on ionization gives two protons. The basicity of sulphuric acid is two. It is a strong acid. It is widely used in industrial preparation of HCl, nitric acid, synthetic detergents, etc.

Complete step by step solution:

Let’s look at the answer of the given question:
Sulphuric acid is a dibasic acid. This means that when dissolved in water it gives two protons which will replace two $^{-}OH$ ions from the solution. The number of replaceable $^{-}OH$ ions is defined as the basicity of an acid.
Sulphuric acid is a strong acid and it gets completely ionized in aqueous solution.
- The chemical reaction for the ionization of sulphuric acid into its ions is:
${{H}_{2}}S{{O}_{4}}\,\to \,2{{H}^{+}}\,+\,\,SO_{4}^{2-}$
- Sulphuric acid on reaction with a base gives both acidic salts and normal salts.
Suppose, sulphuric acid reacts with only 1 mole of NaOH, then it will give an acidic salt.
${{H}_{2}}S{{O}_{4}}\,+\,NaOH\to \,NaHS{{O}_{4}}\,+\,\,{{H}_{2}}O$
is an acidic salt.
Now, when sulphuric acid reacts with two moles of NaOH, it gives a normal salt.
${{H}_{2}}S{{O}_{4}}\,+\,2NaOH\to \,N{{a}_{2}}S{{O}_{4}}\,+\,2\,{{H}_{2}}O$
$N{{a}_{2}}S{{O}_{4}}$is a normal salt.
So, we have seen both the reaction for sulphuric acid to give an acidic or a normal salt.
Therefore, we can conclude that sulphuric acid which is a dibasic salt gives both acidic and normal salts on reaction with a base.
Hence, the answer to the given question is option (C)

Note: Students can confuse sulphuric acid with sulphurous acid which is also a dibasic acid.The second ionization of sulphuric acid is difficult as the $HSO_{4}^{-}$ is resonance stabilized.