Question

Sulphur has highest oxidation state in.

• A. $SO_{2}$
• B. $H_{2}SO_{4}$
• C. $Na_{2}S_{2}O_{3}$
• D. $Na_{2}S_{4}O_{6}$

Answer 1

Answer: (B)

$H_{2}SO_{4}$

Answer 2

$\overset{*}{SO_{2}} = + 4$

$\overset{*}{H_{2}SO_{4}} = + 6$

$\overset{*}{Na_{2}S_{2}O_{3}} = + 2$

$\overset{*}{Na_{2}S_{4}O_{6}} = + \frac{5}{2}$.