Question

Subtract the following; 15 min 24 sec from 37 min 18 sec.

Answer 1

Hint: Use the relation between minutes and seconds. Convert the quantities to seconds first. Subtract them and then convert them back to minutes.

Complete step-by-step answer:
A unit of time is any particular time interval used as a standard way of measuring or expressing duration.
In our daily life, we mostly come across units of time such as seconds, minutes, hours, days, weeks, months, years, etc.
There also exists units of time very smaller than seconds and very larger than years.
In this problem, we come across two units of time, the minutes and the seconds.
We know that 60 seconds is equal to one minute.
Hence, to convert from minutes to seconds, we just multiply the quantity by 60.
15 min 24 sec can be converted into seconds by multiplying 15 with 60 and adding it to 24.
$15\min 24\sec = 15 \times 60 + 24$
$15\min 24\sec = 924\sec ...........(1)$
Hence, 15 min 24 sec is equal to 924 seconds.
37 min 18 sec can be converted into seconds by multiplying 37 with 60 and adding it to 18.
$37\min 18\sec = 37 \times 60 + 18$
$37\min 18\sec = 2238\sec ...........(2)$
Hence, 37 min 18 sec is equal to 2238 seconds.
Using equation (1) and equation (2), we have:
$37\min 18\sec - 15\min 24\sec = 2238 - 924$
$37\min 18\sec - 15\min 24\sec = 1314\sec$
We now divide 1314 by 60 to convert it into minutes.
$\dfrac{{1314}}{{60}} = \dfrac{{1260}}{{60}}\min 54\sec$
$\dfrac{{1314}}{{60}} = 21\min 54\sec$
Hence, the answer is 21 min 54 sec.

Note: You can also attempt to subtract directly but when you have carryover, it should be out of 60 because 1 minute is equal to 60 seconds. So, you have to be careful while subtracting directly in this manner.