Question
Question: <sub>86</sub>A<sup>222</sup>®<sub>84</sub>B<sup>210</sup>. In this reaction how many a and b particl...
86A222®84B210. In this reaction how many a and b particles are emitted-
A
6a, 3b
B
3a, 4b
C
4a, 3b
D
3a, 6b
Answer
3a, 4b
Explanation
Solution
na = 4222−210= 412 = 3
nb = 2na – Z + Z' = 2 × 3 – 86 + 84 = 6 – 2 = 4