Question

Strength of $H_2O_2$ is $15.18\, g\, L^{-1}$, then it is equal to

• A. 1 volume
• B. 10 volume
• C. 5 volume
• D. 7 volume

Answer 1

Answer: (C)

5 volume

Answer 2

Volume strength $=\frac{5.6 \times \text { Strength in } g L^{-1}}{\text { E wt. of } H _{2} O _{2}}$ $=\frac{5.6 \times 15.18}{12} =5$ volumes