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Question: Straight distance between a hotel and a railway station is \( 10km \) , but the circular route is fo...

Straight distance between a hotel and a railway station is 10km10km , but the circular route is followed by a taxi covering 23km23km in 28 minutes28{\text{ minutes}} . What is the average speed and magnitude of average velocity? Are they equal?

Explanation

Solution

So in this question, we have to find the average speed, and as we know that the average speed is given by total path length by the total time. And for the average velocity, we will use the formula which is given by displacement upon a time.

Formula used:
Average speed is given by,
Average speed = Total path lengthTotal timeAverage{\text{ speed = }}\dfrac{{Total{\text{ path length}}}}{{Total{\text{ time}}}}
Average velocity is given by,
Average velocity = DisplacementTimeAverage{\text{ velocity = }}\dfrac{{Displacement}}{{{\text{Time}}}} .

Complete step by step solution:
So in this question, we have the shortest distance given and we know that the shortest distance is the same as the displacement. Also, we have the time given. Now we will first find the average speed.
Therefore, the formula for the average speed is given by
Average speed = Total path lengthTotal timeAverage{\text{ speed = }}\dfrac{{Total{\text{ path length}}}}{{Total{\text{ time}}}}
Now on substituting the values, we get
Average speed = 28(28/60)km/h\Rightarrow Average{\text{ speed = }}\dfrac{{28}}{{\left( {28/60} \right)}}km/h
And on solving the above expression, we will get the equation as
Average speed = 49.3km/h\Rightarrow Average{\text{ speed = 49}}{\text{.3}}km/h
Therefore, the average velocity will be equal to 49.3km/hr49.3km/hr
Now we will calculate the average velocity, so the formula will be given by
Average velocity = DisplacementTimeAverage{\text{ velocity = }}\dfrac{{Displacement}}{{{\text{Time}}}}
Now on substituting the values, we will get the equation as
Average velocity = 10(28/60)km/hrAverage{\text{ velocity = }}\dfrac{{10}}{{\left( {28/60} \right)}}km/hr
And on solving the above expression, we will get the equation as
Average velocity = 21.4km/h\Rightarrow Average{\text{ velocity = 21}}{\text{.4}}km/h
Therefore, the average velocity will be equal to 21.4km/hr21.4km/hr .
Now on comparing the values of the average speed and the average velocity we can see that both are different.
So we can say that the two physical quantities given to us are not equal.

Note:
Here the quantity we have is average speed and this quantity is scalar whereas the average velocity is a vector quantity. Also, one important thing which we have to keep in mind is checking the unit. As in this question too we had changed the unit. So always match the unit before solving it.