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Question

Question: Stopping distance of a moving vehicle is directly proportional to...

Stopping distance of a moving vehicle is directly proportional to

A

Square of the initial velocity

B

Square of the initial acceleration

C

The initial velocity

D

The initial acceleration

Answer

Square of the initial velocity

Explanation

Solution

Let d, is the distance travelled by the vehicle before it stops.

Here, final velocity v = 0, initial velocity = u, S = d, Using equations of motions

v2=u2+2as\mathrm { v } ^ { 2 } = \mathrm { u } ^ { 2 } + 2 \mathrm { as }

(0)2=u2+2ad\therefore ( 0 ) ^ { 2 } = \mathrm { u } ^ { 2 } + 2 \mathrm { ad }

ds=u22ad _ { s } = \frac { u ^ { 2 } } { 2 a }

dsu2\mathrm { d } _ { \mathrm { s } } \propto \mathrm { u } ^ { 2 }