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Question

Physics Question on Acceleration

Stopping distance of a moving vehicle is directly proportional to

A

square of the initial velocity

B

square of the initial acceleration

C

the initial velocity

D

the initial acceleration

Answer

square of the initial velocity

Explanation

Solution

Let dsd_s is the distance travelled by the vehicle before it stops. Here, final velocity v=0v = 0, initial velocity =u= u, S=dsS = d_s Using equation of motion v2=u2+2aSv^2=u^2+2aS (0)2=u2+2ads\therefore \left(0\right)^{2}=u^{2}+2ad_{s}; ds=u22ad_{s}=-\frac{u^{2}}{2a} or dsu2d_{s} \propto u^{2}