Question

Stationary waves of frequency 300 Hz are formed in a medium in which the velocity of sound is 1200 metre/sec. The distance between a node and the neighbouring antinode is

• A. 1 m
• B. 2 m
• C. 3 m
• D. 4 m

Answer 1

Answer: (A)

1 m

Answer 2

Required distance $= \frac{\lambda}{4} = \frac{v/n}{4} = \frac{1200}{4 \times 300} = 1m$