Question

Stationary waves are set up in air column. Velocity of sound in air is 330 m/s and frequency is 165 Hz. Then distance between the nodes is –

• A. 2m
• B. 1m
• C. 0.5 m
• D. 4m

Answer 1

Answer: (B)

1m

Answer 2

Distance between the nodes = l/2

v = vl ̃ l = $\frac{330}{165}$ = 2

1m