Question
Physics Question on Semiconductor electronics: materials, devices and simple circuits
Statement I: When a Si sample is doped with Boron, it becomes P type and when doped by Arsenic it becomes N-type semi conductor such that P-type has excess holes and N-type has excess electrons.
Statement II: When such P-type and N-type semi-conductors, are fused to make a junction, a current will automatically flow which can be detected with an externally connected ammeter.
In the light of above statements, choose the most appropriate answer from the options given below
Statenent I is correct but statement II is incorrect
Both Statement I and Statement II are incorrect
Statenent I is incorrect but statement II is correct
Both Statenent I and statement II are correct
Statenent I is correct but statement II is incorrect
Solution
The correct option is(A): Statenent I is correct but statement II is incorrect.
When P-N junction is formed an electric field is generated form N-side to P-side due to which barrier potential arises & majority charge carrier can not flow through the junction due to barrier potential so current is zero unless we apply forward bias voltage.