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Question: Statement I: \(_2^4He\) is the correct symbol for an alpha particle Because Statement II: An alp...

Statement I: 24He_2^4He is the correct symbol for an alpha particle
Because
Statement II: An alpha particle is a helium-3 nucleus
A.True True CE
B.True True
C.True False
D.False True
E.False False

Explanation

Solution

In this question, we have to tell whether the given statements are true or false. Helium is a chemical element with the symbol HeHe and atomic number 2. Its electronic configuration is 1s21{s^2} . It is a colorless, tasteless, odorless, and non-toxic, inert, monoatomic gas, the first in the noble gas group in the periodic table.

Complete step by step answer:
Now we will discuss the given statements.
For statement I: 24He_2^4He is the correct symbol for an alpha particle because an alpha particle is identical to a helium atom. Thus, an alpha particle contains two protons and neutrons. An alpha particle has no electrons to balance the positive charge of the two protons and can be represented as He2+H{e^{2 + }}. So statement I is true.
For statement II: An alpha particle is a helium-3 nucleus. Since helium contains two protons and two neutrons, therefore, an alpha particle is a helium-4 nucleus. So statement II is false.
After discussing the given statements we can say that statement I is true and statement II is false.
Hence, the correct option is (C).

Note:
Alpha particle is equivalent to the nucleus. It is represented by α2p+2x{\alpha ^{2p + 2x}} (24He)\left( {_2^4He} \right).They have a, +2 + 2 charge so they are highly ionizable. Alpha particles have the least penetrating power among the others and the least speed in comparison to beta particles and gamma particles. 92236U90232Y+24α+E_{92}^{236}U \to _{90}^{232}Y + _2^4\alpha + E
Here Y is the element formed after the emission of an alpha particle from uranium.
Alpha particles are heaviest among the beta and gamma particles.
Alpha particles have less speed in comparison to beta and gamma particles.