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Question: Statement A. The electric field generated from Gauss's law is path-independent. Statement B: The el...

Statement A. The electric field generated from Gauss's law is path-independent.

Statement B: The electric field generated due to a changing magnetic flux is also path-independent.

Question: Which of the above statements are correct?

A

Only A is correct.

B

Only B is correct.

C

Both A and B are correct.

D

Neither A nor B is correct.

Answer

Only Statement A is correct.

Explanation

Solution

Statement A refers to the electrostatic field, which is conservative, meaning the work done by the field (and thus the line integral) is path-independent. Statement B refers to the induced electric field due to changing magnetic flux (Faraday's law), which is non-conservative, meaning the line integral around a closed path is non-zero, implying path-dependence for line integrals between points.

Statement A: The electric field generated from Gauss's law is path-independent. Gauss's law is a fundamental law of electrostatics, dealing with electric fields produced by static charge distributions. The electric field in electrostatics is a conservative field. For a conservative field E\vec{E}, the line integral ABEdl\int_A^B \vec{E} \cdot d\vec{l} between any two points A and B is independent of the path taken. This property is known as path-independence. Thus, Statement A is correct.

Statement B: The electric field generated due to a changing magnetic flux is also path-independent. According to Faraday's law of electromagnetic induction, a changing magnetic flux induces an electromotive force (EMF), which is associated with an induced electric field. Faraday's law is given by Edl=dΦBdt\oint \vec{E} \cdot d\vec{l} = -\frac{d\Phi_B}{dt}. The integral on the left side is the circulation of the electric field around a closed loop. If the magnetic flux ΦB\Phi_B is changing with time (dΦBdt0\frac{d\Phi_B}{dt} \neq 0), the line integral of the induced electric field around a closed path is non-zero. This property (Edl0\oint \vec{E} \cdot d\vec{l} \neq 0) defines a non-conservative field. For a non-conservative field, the line integral between two points is dependent on the path taken. Therefore, the electric field generated due to a changing magnetic flux is path-dependent. Thus, Statement B is incorrect.