Question
Question: Statement 1: According to the equation \({M_1}{V_1} = {M_2}{V_2}\) , as the volume increases the mol...
Statement 1: According to the equation M1V1=M2V2 , as the volume increases the molarity decreases
Because
Statement 2: As water is added to solution the solution is diluted
(A) One is true, second is true and current explanation of statement
(B) One is true and second is wrong
(C) True and false
(D) One is false, second is true
(E) False and false
Solution
Hint - To proceed towards the answer to this problem, firstly we should understand about Molarity, its formula and the concepts behind these terms. We will also study how to find out the molality when the volume is changed. And hence, by using this knowledge we can easily approach our answer.
Complete step by step solution:
Molarity - Molarity(M) of a solution states that the number of moles of solute dissolved per litre of solution. It does not depend on temperature
Molarity=VolumeofsolutioninlitresNo.ofmolesofsolute
If a solution having molarityM1 and volumeV1 is diluted to volumeV2 so that the new molarity is M2 then as the total number of moles will remain constant,
M1V1=M2V2
Molarity can be used to measure the volume of solvent or the amount of solute. The correlation between two solution with the same number of moles of solute can be represented by the formula
c1V1=c2V2, wherec is the concentration and V is the volume. The concentration of a substance in solution, expressed as the number moles solute per liter of solution.
Statement 1: According to the equationM1V1=M2V2
As the volume increases the molarity decreases
Because
Statement 2: As water is added to a solution the solution is diluted.
So, the correct answer to this problem is option A.
One is true, second is true and correct explanation of statement
Note - With the increase in the dilution, the number of moles per unit volume decreases and the molarity of the solution is the number of moles of solute per unit volume of solution. Molarity is the way by which we can measure how much of a specific element or compound has been dissolved.