Question

State with reason:
Which is more polar $C{O_2}$ or ${N_2}O$ ?

Answer 1

In order to answer this question, we should know about the definition of polarity and the factors on which polarity depends. For this question, we should also know about the concept of the dipole moment of a molecule.

Complete Step By Step Answer:
Let us understand the complete answer in detail.
We know that polarity and non- polarity of the molecules depends on their electronegativity differences. There could be two possibilities of the types of bond i.e. polar and nonpolar bond. When there is no difference in electronegativity of molecules, then bonds will be nonpolar bonds whereas if there is a difference in electronegativity then the bond will be completely polar.
The electronegativity difference is a net dipole moment between the bonds. If the net dipole moment is zero then it indicates the bond will be nonpolar but if the net dipole moment indicates some value then it will be a polar bond.
In the above question, there are two molecules given i.e. $C{O_2}$ and ${N_2}O$ . ${N_2}O$ is more polar than $C{O_2}$ . The reason is explained below:
We know that $C{O_2}$ is a linear and symmetrical molecule so the net dipole moment is zero. Hence, it is non polar.
Now, ${N_2}O$ is also linear and symmetrical but it is considered as the resonance hybrid of two structures due to which its net dipole moment is $0.116D$ . Hence, it is polar.

Note:
It must be remembered that the main factor is the electronegativity difference in the molecules which predicts the polarity of the bond. Also, remember that polar molecules dissolve only in polar solvents and nonpolar dissolves in non-polar solvents.