Question
Question: State law of reciprocal proportion with an example....
State law of reciprocal proportion with an example.
Solution
The law of reciprocal proportions states that “If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine.”
Complete answer:
The law seems to be complicated to understand. For a better understanding, let’s consider an example-
An example is when 3 grams of carbon reacts with 1 gram of hydrogen in order to form methane.
And, when 8 grams of oxygen reacts with 1 gram of hydrogen to form water.
The ratio of their masses i.e mass ratio is C:O = 3:8
In this manner, 12 grams of carbon react with 32 grams of oxygen in order to form carbon dioxide.
The ratio of their masses i.e mass ratio is C:O = 12:32 = 3:8
The mass ratio in which carbon and oxygen combine is similar to the mass ratio in which they combine separately with a fixed mass of H.
When 12 grams of carbon is reacting with 16 grams of oxygen in order to form carbon monoxide
The mass ratio of C:O = 12:16 = 3:4
The ratio of masses in which they react separately has a fixed mass of hydrogen i.e 3:8.
Now, we will find out the ratio of the two ratios i.e 8343= 2:1
So, the ratio in which carbon and oxygen combine is twice the ratio in which they get combined with a fixed mass of hydrogen.
Note:
Jeremias Richter proposed the law of reciprocal proportions, he utilizes the law for neutralization of ratios of metals with the acids. It mentioned that if two substances A and B are reacting chemically with the other substances C and D, then the ratio of the quantities of C and D has the same amount of A as the ratio of the quantities of C and D has with B.