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Question: State (i) Van’t Hoff-Boyles law (ii) Van’t Hoff Charles law...

State (i) Van’t Hoff-Boyles law (ii) Van’t Hoff Charles law

Explanation

Solution

Hint: Both the laws given in question are derived and stated from the ideal gas equation. Boyle’s law states that pressure is inversely proportional to the volume you can imagine this law by taking a piston as an example. Charle’s law states that volume is directly proportional to temperature. Imagine an example of boiling water.

Complete step-by-step answer:
(i) Van’t Hoff-Boyle;s law:
Boyle's law states that at constant temperature the pressure exerted by a fixed mass of a gas is inversely proportional to volume occupied by the gas.
Pα1VP\alpha \dfrac{1}{V},at constant temperature
PV=constant
Where,
P= pressure of a enclosed gas
V=volume of a enclosed gas
Boyle's law can be derived on the basis of kinetic theory of gases.
Consider a gas of volume V and N molecules, each of mass m.
Mass of gas M=Nm
According to kinetic theory of gases pressure exerted is given by
P=13ρCRMS2 P=13MVCRMS2 PV=13M1CRMS2 PV=23N(12mCRMS2) \begin{aligned} & P=\dfrac{1}{3}\rho C_{RMS}^{2} \\\ & P=\dfrac{1}{3}\dfrac{M}{V}C_{RMS}^{2} \\\ & PV=\dfrac{1}{3}\dfrac{M}{1}C_{RMS}^{2} \\\ & PV=\dfrac{2}{3}N\left( \dfrac{1}{2}mC_{RMS}^{2} \right) \\\ \end{aligned}
The quantity 12mCRMS2\dfrac{1}{2}mC_{RMS}^{2}. The average kinetic energy of gas molecules remains constant at constant temperature according to the assumption.
Therefore, PV=Constant
Pα1VP\alpha \dfrac{1}{V}, and this is Boyle’s law.

(ii)Van’t Hoff Charle’s:
Charle’s law states that at a fixed pressure the volume is proportional to its absolute temperature.
I.e. PαTP\alpha T
VT=k=constant\dfrac{V}{T}=k=cons\tan t
Where k is the constant which depends on pressure of gas, the amount of gas and also the unit of volume.
If V1andT1{{V}_{1}} and {{T}_{1}} are the initial values of volume and temperature of a gas then, V1T1=k\dfrac{{{V}_{1}}}{{{T}_{1}}}=k
Also, if the temperature is now changed to T2{{T}_{2}} such that the volume changes to V2{{V}_{2}}
It can be written as
V2T2=k\dfrac{{{V}_{2}}}{{{T}_{2}}}=k
Therefore we can write as,

& \dfrac{{{V}_{1}}}{{{T}_{1}}}=\dfrac{{{V}_{2}}}{{{T}_{2}}} \\\ & {{V}_{1}}{{T}_{1}}={{V}_{2}}{{T}_{2}} \\\ \end{aligned}$$ This is Charle’s law. Note: Constant in Boyle’s law depends on pressure and volume of gas contained in the container. While constant in charles's law depends on temperature and volume. Students should not be mug derivation and concept. You can get all relations from the ideal gas equation.