Starting with the same initial conditions, an ideal gas expa... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Starting with the same initial conditions, an ideal gas expands from volume V $_1$ to V $_2$ in three different ways, the work done by the gas is W $_1$ if the process is purely isothermal, W $_2$ if purely isobaric and W $_3$ if purely adiabatic, then

A

$W_2 > W_1 > W_3$

B

$W_2 > W_3 > W_1$

C

$W_1 > W_2 > W_3$

D

$W_1 > W_3 > W_2$

Answer

$W_2 > W_1 > W_3$

Explanation

Solution

The corresponding p-V graphs (also called indicator diagram) in three different processes will be as shown :
Area under the graph gives the work done by the gas.
(Area ) $_2$ > (Area) $_1$ > (Area ) $_3$
$\therefore \, \, \, \,$ W $_2$ > W $_1$ > W $_3$