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Question

Physics Question on Thermodynamics

Starting with the same initial conditions, an ideal gas expands from volume V1{{V}_{1}} to V2{{V}_{2}} in three different ways. The work done by the gas is W1{{W}_{1}} if the process purely isothermal, W2{{W}_{2}} if purely isobaric and W3{{W}_{3}} if purely adiabatic. Then

A

W2>W1>W3{{W}_{2}}>{{W}_{1}}>{{W}_{3}}

B

W2>W3>W1{{W}_{2}}>{{W}_{3}}>{{W}_{1}}

C

W1>W2>W3{{W}_{1}}>{{W}_{2}}>{{W}_{3}}

D

W1>W3>W2{{W}_{1}}>{{W}_{3}}>{{W}_{2}}

Answer

W2>W1>W3{{W}_{2}}>{{W}_{1}}>{{W}_{3}}

Explanation

Solution

Work done is equal to area under the curve on p-V diagram. This is largest for isobaric process and least for adiabatic expansion.