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Question: Starting with a sample of pure \(66Cu,\frac{7}{8}\) of it decays into Zn in 15 min. The correspondin...

Starting with a sample of pure 66Cu,7866Cu,\frac{7}{8} of it decays into Zn in 15 min. The corresponding half-life is.

A

5 min

B

7127\frac{1}{2} min

C

10 min

D

15 min

Answer

5 min

Explanation

Solution

78\frac{7}{8}part decays i.e. remaining part is 18\frac{1}{8}.

N=N0(12)tT1/218=(12)15T1/2T1/2N = N_{0}\left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}} \Rightarrow \frac{1}{8} = \left( \frac{1}{2} \right)^{\frac{15}{T_{1/2}}} \Rightarrow T_{1/2}=5 min.