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Question

Physics Question on Half life

Starting with a sample of pure 66Cu,7/8{ }^{66} Cu , 7 / 8 of it decays into ZnZn in 15min15 \,min. The corresponding half-life is

A

10 min

B

15 min

C

5 min

D

7127 \frac{1}{2} min

Answer

5 min

Explanation

Solution

N=N0(1eλt)N = N_{0}\left(1-e^{-\lambda t}\right) N0NN0=eλt\Rightarrow \frac{N_{0}-N}{N_{0}}=e^{-\lambda t} 18=eλt\frac{1}{8} =e^{-\lambda t} 8=eλt\therefore 8 =e^{\lambda t} 3ln2=λt\Rightarrow 3 \ln 2 =\lambda t λ=3×0.69315\Rightarrow \lambda=\frac{3 \times 0.693}{15} Half-life period t1/2=0.6933×0.693×15t_{1 / 2} =\frac{0.693}{3 \times 0.693} \times 15 t1/2=5mint_{1 / 2} =5 \min