Question

Starting from propanoic acid, the following reactions were carried out

Propanoicacid $\xrightarrow { \mathrm { NH } _ { 3 } }$Y$\xrightarrow { \mathrm { Br } _ { 2 } + \mathrm { KOH } }$ Z

What is the compound Z

• A. CH3–CH2–Br
• B. CH3–CH2–NH2
• C.
• D. CH3–CH2–CH2–NH2

Answer 1

Answer: (B)

CH3–CH2–NH2

Answer 2

CH3CH2COOH $\xrightarrow { \mathrm { SOCI } _ { 2 } }$ CH3CH2COCl $\xrightarrow { \mathrm { NH } _ { 3 } }$ CH3CH2CONH2 $\xrightarrow { \mathrm { Br } _ { 2 } + \mathrm { KOH } }$ CH3CH2NH2