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Question

Physics Question on doppler effect

Standing waves are produced in 10m10\, m long stretched string. If the string vibrates in 55 segments and wave velocity is 20m/s20\,m/s, its frequency is

A

5 Hz

B

4 Hz

C

2 Hz

D

10 Hz

Answer

5 Hz

Explanation

Solution

As standing waves are produced in the string and the string is vibrating in 5 segments, it can be shown as
5λ2=10\therefore 5 \frac{\lambda}{2}=10
λ=4m\Rightarrow \lambda=4\, m
Given, the velocity of the wave v=20m/sv=20\, m / s
\therefore Frequency v=vλ=204=5s1=5Hzv=\frac{v}{\lambda}=\frac{20}{4}=5\, s ^{-1}=5\, Hz