Question

Standing wave are produced in a $10 \,m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 \,m/s$. The frequency is:

• A. 10 Hz
• B. 5 Hz
• C. 4 Hz
• D. 2 Hz

Answer 1

Answer: (B)

5 Hz

Answer 2

$n=\frac{p}{2 l} \sqrt{\frac{T}{m}}=\frac{p v}{2 l}$
$=\frac{5 \times 20}{2 \times 10}=5\, Hz$