Question
Question: \(\sqrt{3} + 1\) =...
3+1 =
A
3
B
2+3
C
z1
D
z2
Answer
z1
Explanation
Solution
R.H.S = (cosθ2+isinθ2)
∴ ∣z1+z2∣=[(r1cosθ1+r2cosθ2)2
+(r2sinθ1+r2sinθ2)2]1/2
3+1 =
3
2+3
z1
z2
z1
R.H.S = (cosθ2+isinθ2)
∴ ∣z1+z2∣=[(r1cosθ1+r2cosθ2)2
+(r2sinθ1+r2sinθ2)2]1/2