Question

$\sqrt{2\{ x\}^{2} - 3\{ x\} + 1}$ equals to

• A. 2
• B. 0
• C. – 2
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

= 1,

because for values to the right of 5, x – 5 > 0, so $| x - 5 |$

= (x – 5).

$\lim _ { x \rightarrow 5 ^ { - } } \frac { x - 5 } { | x - 5 | } = \lim _ { x \rightarrow 5 ^ { - } } - 1$ = – 1

because for values to the left of 5, x – 5 < 0, so $| x - 5 |$

= – (x – 5)

⇒ $\lim _ { x \rightarrow 5 } \frac { x - 5 } { | x - 5 | }$ doesn’t exist