(\sqrt{3}x + \sqrt{2}y = 2\sqrt{2}) ; (\sqrt{2}x - \sqrt{3}y... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

$\sqrt{3}x + \sqrt{2}y = 2\sqrt{2}$ ; $\sqrt{2}x - \sqrt{3}y = 3\sqrt{3}$ implies $x=,y=$

A

1,2

B

$\sqrt{6},-1$

C

2,1

D

$\sqrt{2},\sqrt{3}$

Answer

$\sqrt{6},-1$

Explanation

Solution

The correct option is (B): $\sqrt{6},-1$