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Question: Spring of constant k fixed to its front wall. A body stretches this spring by distance x and in the ...

Spring of constant k fixed to its front wall. A body stretches this spring by distance x and in the mean time the compartment moves by a distance s. The work done by boy with reference to earth is

A

12\frac { 1 } { 2 } kx2

B

12\frac { 1 } { 2 } (kx) (s + x)

C

12\frac { 1 } { 2 } kxs

D

12\frac { 1 } { 2 } kx(s + x + s)

Answer

12\frac { 1 } { 2 } kx2

Explanation

Solution

Work done by man to stretch the spring

= (12kx)(S+x)\left( \frac { 1 } { 2 } \mathrm { kx } \right) ( \mathrm { S } + \mathrm { x } )

Work done by man on the floor =

∴ Total work done = 12kx2\frac { 1 } { 2 } \mathrm { kx } ^ { 2 }