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Question

Chemistry Question on coordination compounds

Spin only magnetic moment of [MnBr6]4- is _____B.M. [round off to the closest integer]

Answer

The correct answer is 6
[MnBr6]–4
x – 6 = –4
x = + 2 Mn = 3d54s2
Mn+2 = 3d54s0
n = 5
μ=n(n+2)μ = \sqrt{n(n+2)}
=356B.M.= \sqrt{35} ≈ 6 B.M.