Question

Spin magnetic moment of Xn+ (Z = 26) is B.M. Hence number of unpaired electrons and value of n respectively are :

• A. 4, 2
• B. 2, 4
• C. 3, 1
• D. 0, 2

Answer 1

Answer: (A)

4, 2

Answer 2

Magnetic moment $= \sqrt{n(n + 2)} = B.M.$

$\therefore$ No. of unpaired electron = 4.

X26 : 1s2 2s22p63s23p63d64s2.

To get 4 unpaired electrons, outermost configuration will be 3d6.

$\therefore$ No. of electrons lost = 2 (from 4s2).

$\therefore$ n = 2.