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Question

Physics Question on doppler effect

speeds of 20m/s20\, m/s and 15m/s15\, m/s relative to the ground. The first train sounds a whistle of frequency 600Hz600\, Hz. The frequency of the whistle heard by a passenger in the second train before the train meets, is (the speed of sound in air is 340 m/s)

A

600 Hz

B

585 Hz

C

645 Hz

D

666 Hz

Answer

666 Hz

Explanation

Solution

The frequency of whistle heard by passenger in the train B, is
n=(v+v0vvs)n =\left(\frac{ v + v _{0}}{ v - v _{ s }}\right)
=600(340+1534020)666Hz=600\left(\frac{340+15}{340-20}\right) \approx 666\, Hz