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Question

Physics Question on laws in physics

Speed of light in vacuum is given by 3×108ms13 \times 10^8\, m\, s^{-1} in MKSMKS system. If in a new system, the unit of length and time is increased by a factor of 22 and 44, respectively, then the numerical value of speed of light in this new system will be

A

3×1083 \times 10^8

B

6×1086 \times 10^8

C

1.5×1081.5 \times 10^8

D

9×1089 \times 10^8

Answer

6×1086 \times 10^8

Explanation

Solution

As n1u1=n2u2n_1\,u_1=n_2\,u_2 n2=(u1u2)n1=(L1T11L2T21)(n1)\Rightarrow n_{2}=\left(\frac{u_{1}}{u_{2}}\right)n_{1}=\left(\frac{L_{1}T^{-1}_{1}}{L_{2}T^{-1}_{2}}\right)\left(n_{1}\right) =(12×4)(3×108)=6×108=\left(\frac{1}{2}\times4\right)\left(3\times10^{8}\right)=6\times10^{8}