Question
Physics Question on laws in physics
Speed of light in vacuum is given by 3×108ms−1 in MKS system. If in a new system, the unit of length and time is increased by a factor of 2 and 4, respectively, then the numerical value of speed of light in this new system will be
A
3×108
B
6×108
C
1.5×108
D
9×108
Answer
6×108
Explanation
Solution
As n1u1=n2u2 ⇒n2=(u2u1)n1=(L2T2−1L1T1−1)(n1) =(21×4)(3×108)=6×108