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Question

Physics Question on Bohr's model of hydrogen atom

Speed of an electron in Bohr's 7th 7^{\text {th }} orbit for Hydrogen atom is 36×106m/s36 \times 10^6 m / s. The corresponding speed of the electron in 3rd 3^{\text {rd }} orbit, in m/sm / s is :

A

(3.6×106)\left(3.6 \times 10^6\right)

B

(7.5×106)\left(7.5 \times 10^6\right)

C

(1.8×106)\left(1.8 \times 10^6\right)

D

(8.4×106)\left(8.4 \times 10^6\right)

Answer

(8.4×106)\left(8.4 \times 10^6\right)

Explanation

Solution

Vn​∝nZ​
Z=1,
∴Vn​∝n1​
∴V7​V3​​=37​
∴V3​=37​V7​
=37​×3.6×106m/s
=8.4×106m/s