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Question: Specific conductance of \(0.1M\) NaCl solution is \(1.01 \times 10^{2}ohm^{- 1}cm^{- 1}\)its molar c...

Specific conductance of 0.1M0.1M NaCl solution is 1.01×102ohm−1cm−11.01 \times 10^{2}ohm^{- 1}cm^{- 1}its molar conductance in ohm−1cm2mol−1ohm^{- 1}cm^{2}mol^{- 1} is

A

1.01×1021.01 \times 10^{2}

B

1.01×1031.01 \times 10^{3}

C

1.01×1041.01 \times 10^{4}

D

10.110.1

Answer

1.01×1021.01 \times 10^{2}

Explanation

Solution

Δm=k×1000M\Delta_{m} = \frac{k \times 1000}{M}

=1.01×10−2×10000.1=1.01×102ohm−1cm2mol−1= \frac{1.01 \times 10^{- 2} \times 1000}{0.1} = 1.01 \times 10^{2}ohm^{- 1}cm^{2}mol^{- 1}