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Question

Physics Question on Units and measurement

Sometimes it is convenient to construct a system of units so that all quantities can be expressed in terms of only one physical quantity. In one such system, dimensions of different quantities are given in terms of a quantity XX as follows: [[ position ]=[Xα];[]=\left[X^{\alpha}\right] ;[ Speed ]=[Xβ];[]=\left[X^{\beta}\right] ;[ acceleration ]=[Xp];[]=\left[X^{p}\right] ;[ Linear momentum ]=[Xq];]=\left[X^{q}\right] ; [force] =[Xr]=\left[X^{ r }\right]. Then

A

α+p=2β\alpha+ p =2 \beta

B

p+qr=βp + q - r =\beta

C

pq+r=αp - q + r =\alpha

D

p+q+r=βp + q + r =\beta

Answer

α+p=2β\alpha+ p =2 \beta

Explanation

Solution

Both the options A and B are Correct.
α+p=2β\alpha+ p =2 \beta
p+qr=βp + q - r =\beta