Question
Question: Some of the wavelengths observed in the emission spectrum of neutral hydrogen gas are: 912,1026, 121...
Some of the wavelengths observed in the emission spectrum of neutral hydrogen gas are: 912,1026, 1216, 3646, 6563 Ao. If broadband light is passing through neutral hydrogen gas at room temperature, the wavelength that will not be absorbed strongly is?
A. 1026 Ao
B. 1216 Ao
C. 912 Ao
D. 3646 Ao
Solution
Hint: We need to find the range of wavelengths that we will be absorbed in the hydrogen spectrum. For this, we will apply the Rydberg formula and obtain the range. Once we get the range it will be easy to check the wrong option i.e the wavelength that will not be absorbed strongly.
Complete step-by-step answer:
Rydberg formula for Hydrogen is:
λ1=Rh(n121−n221)
We need to get the smallest and longest wavelength of the spectrum. So, what are the values of n1 and n2 for the smallest and longest wavelength? The highest wavelength will be for n1 = 1 and n2 = 2. The smallest wavelength will be for n1 = 1 and n2 = infinite. So let’s find the largest wavelength.
λ1=Rh(11−41)
1/λ=Rh(3/4)
λ1=Rh(43)
λ=3Rh4
The value of Rh is
Rh =1.0967×107m−1
λ=3×1.0967×1074
λ=1.2158×10−7
λ=12158×10−10
λ=1216Ao
Similarly, if we calculate the shortest wavelength
λ1=Rh(11)
λ=Rh1
The value of Rh is
Rh = 1.0967×107m−1
λ=1.0967×1071
λ=0.9118×10−7
λ=912Ao
The range of the wavelengths is 911A - 1216A
In the given options 3646A is not in the range. So it will not be absorbed strongly.
Note: It is very handy to remember λ1 value as it is often seen in calculations. The value of the λ1 value is 912A. We can also find the frequency range from there we can find the wavelength range.