Question

Some equipotential surface are shown in the figure. The magnitude and direction of the electric field is

• A. 100 V/m making angle 120^o with the x-axis
• B. 100 V/m making angle 60^o with the x-axis
• C. 200 V/m making angle 120^o with the x-axis
• D. None of the above

Answer 1

Answer: (C)

200 V/m making angle 120^o with the x-axis

Answer 2

By using $dV = Edr\cos\theta$ suppose we consider line 1 and line 2 then

(30 – 20) = E cos 60^o (20 – 10) × 10^–2

So $E = 200volt/m$ making in angle 120^o with x-axis