Question

Some amount of urea is added to 1000 gm of H2O due to which vapor pressure decreases by 25% of the original vapor pressure. Find out the mass of urea added (Round off to two decimal places)

Answer 1

The correct answer is : 18.52

$\frac{25}{75}=\frac{n_{urea}}{\frac{1000}{18}}$

$\Rightarrow n_{urea}=\frac{1}{3}\times \frac{1000}{18}=18.52$