Question
Mathematics Question on Reducing Equations to Simpler Form
Solve the linear equation: m−2m−1=1−3m−2
Answer
m−2m−1=1−3m−2
L.C.M. of the denominators, 2 and 3, is 6.
Multiplying both sides by 6, we obtain
6m−3(m−1)=6−2(m−2)
⇒ 6m−3m+3=6−2m+4 (Opening the brackets)
⇒ 6m−3m+2m=6+4−3
⇒ 5m=7
⇒ m=57