Question
Question: Solve the following: \(\tan (1/2{{\sin }^{-1}}3/4)\)...
Solve the following: tan(1/2sin−13/4)
Solution
Revise all the formulas of trigonometry and all the properties of inverse trigonometric functions. The inverse trigonometric functions are the inverse functions of the trigonometric functions for example inverse of sine, cosine, tangent etc.
Complete step by step solution:
We have to solve tan(1/2sin−13/4) for that let us assume that
1/2sin−13/4=θ
Now by cross multiplication
1/2sin−13/4=θ becomes
sin−13/4=2θ ---- (1)
Now by multiplying sin on both sides of the equation(1)
sin(sin−13/4)=sin2θ
sin2θ=3/4 ---- (2)
Now by using the formula sin2θ=2tanθ/(1+tan2θ) on equation (2)
2tanθ/(1+tan2θ)=3/4
Now by cross multiplication
2tanθ/(1+tan2θ)=3/4 becomes
4(2tanθ)=3(1+tan2θ) ----- (3)
By solving the brackets of equation (3)
8tanθ=3+3tan2θ
3tan2θ−8tanθ+3=0 ------- (4)
To find the roots of a quadratic equation we use the formula
x=2a−b±b2−4ac
So by using the above formula on equation (4)
tanθ=−(−8)±64−(4×3×3/2×3
So, tanθ=4±7/3 ----- (5)
Now by taking tan inverse on both sides of equation (5)
θ=tan−1[4±7/3]
tanθ=4±7/3
As θ=1/2sin−13/4
So, tanθ=4±7/3
Since ,
−π/2≤sin−13/4≤π/2−π/4≤1/2sin−13/4≤π/4
Therefore, tan(−π/4)≤tan1/2(sin−13/4)≤tanπ/4
−1≤tan(1/2sin−13/4)≤1
Since, 4+7/3>1 so it is ignored
Therefore, tan(1/2sin−13/4)=4−7/3.
Note:
There is a restriction on sinθ i.e. −π/2≤sin−1θ≤π/2. So all the values which are greater than one should be ignored. Always use the correct trigonometric formula to solve a particular equation as using the wrong formula leads towards the wrong answer.